7[t-3]+1=3[t+4]

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Solution for 7[t-3]+1=3[t+4] equation:


Simplifying
7[t + -3] + 1 = 3[t + 4]

Reorder the terms:
7[-3 + t] + 1 = 3[t + 4]
[-3 * 7 + t * 7] + 1 = 3[t + 4]
[-21 + 7t] + 1 = 3[t + 4]

Reorder the terms:
-21 + 1 + 7t = 3[t + 4]

Combine like terms: -21 + 1 = -20
-20 + 7t = 3[t + 4]

Reorder the terms:
-20 + 7t = 3[4 + t]
-20 + 7t = [4 * 3 + t * 3]
-20 + 7t = [12 + 3t]

Solving
-20 + 7t = 12 + 3t

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-3t' to each side of the equation.
-20 + 7t + -3t = 12 + 3t + -3t

Combine like terms: 7t + -3t = 4t
-20 + 4t = 12 + 3t + -3t

Combine like terms: 3t + -3t = 0
-20 + 4t = 12 + 0
-20 + 4t = 12

Add '20' to each side of the equation.
-20 + 20 + 4t = 12 + 20

Combine like terms: -20 + 20 = 0
0 + 4t = 12 + 20
4t = 12 + 20

Combine like terms: 12 + 20 = 32
4t = 32

Divide each side by '4'.
t = 8

Simplifying
t = 8

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